A) \[\left( {{F}_{1}},\,{{F}_{2}} \right)\in R,\,\left( {{F}_{2}},\,{{F}_{3}} \right)\in R\] and \[\left( {{F}_{1}},\,{{F}_{3}} \right)\in R\]
B) \[\left( {{F}_{1}},\,{{F}_{2}} \right)\in R,\,\left( {{F}_{2}},\,{{F}_{3}} \right)\in R\] and \[\left( {{F}_{1}},\,{{F}_{3}} \right)\notin R\]
C) \[\left( {{F}_{1}},\,{{F}_{2}} \right)\in R,\,\left( {{F}_{2}},\,{{F}_{2}} \right)\in R\] not \[\left( {{F}_{3}},\,{{F}_{3}} \right)\notin R\]
D) \[\left( {{F}_{1}},\,{{F}_{2}} \right)\notin R,\,\left( {{F}_{2}},\,{{F}_{3}} \right)\notin R\] and \[\left( {{F}_{1}},\,{{F}_{3}} \right)\notin R\]
Correct Answer: A
Solution :
Clearly \[\left( {{F}_{1}},\,{{F}_{2}} \right)\in R\], \[\left( {{F}_{2}},\,{{F}_{3}} \right)\in \,R\] and \[\left( {{F}_{1}},\,{{F}_{3}} \right)\in R\].You need to login to perform this action.
You will be redirected in
3 sec