A) \[{{6}^{2}}\]
B) \[{{2}^{6}}\]
C) 6!
D) \[{{2}^{12}}\]
Correct Answer: D
Solution :
\[R=\left\{ \left( 1,\,1 \right),\,\left( 1,\,2 \right),\,\left( 1,3 \right),\,\left( 1,4 \right)\,\left( 1,\,5 \right),\,\left( 1,6 \right) \right.\] \[\left. \left( 2,\,2 \right),\,\left( 2,\,4 \right),\,\left( 2,\,6 \right),\,\left( 3,\,3 \right),\,\left( 3,\,6 \right),\,\left( 4,\,4 \right),\left( 5,5 \right),\,\left( 6,\,6 \right) \right\}\] Number of relations from A to B \[={{2}^{n\left( A \right)\times n\left( B \right)}}={{2}^{2\times 6}}={{2}^{12}}\].
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