A) \[i\,=1-\alpha \]
B) \[i\,=1+\alpha \]
C) \[i\,=1-\alpha /2\]
D) \[i\,=1+\alpha /2\]
Correct Answer: C
Solution :
\[\alpha =\frac{i-1}{\left( \frac{1}{n}-1 \right)}=\frac{\left( i-1 \right)}{\left( \frac{1}{2}-1 \right)}\] \[\left( i-1 \right)=-\frac{1}{2}\alpha \] or \[i=1-\frac{1}{2}\alpha \]You need to login to perform this action.
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