A) \[3\centerdot 38g\]
B) \[0\centerdot 33g\]
C) 3380 g
D) \[33\centerdot 8g.\]
Correct Answer: A
Solution :
\[\pi =i.\frac{{{W}_{2}}RT}{{{M}_{2}}V}\] \[{{W}_{2}}=\frac{\pi .{{M}_{2}}.V}{i.R.T}=\frac{0.75\times 111\times 2.5}{2.5\times 0.0821\times 300}\] =3.38 g
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