| Direction (6 - 10): Antifreeze prevents the freezing of water in the car radiator in subzero conditions. An antifreeze solution is prepared from 222.6 g of ethylene glycol and 200 g of water to be used by a family during their trip to Gulmarg. |
A) \[1\centerdot 79m\]
B) \[17\centerdot 1m\]
C) \[17\centerdot 95m\]
D) \[18\centerdot 55m\]
Correct Answer: C
Solution :
Mass of ethylene glycol = \[222\centerdot 6g\] Molar mass of ethylene glycol = 2 \[\times \] 12 + 6 \[\times \] 1 + 2 \[\times \] 16 = 62 g mol-1 Mass of water = 200 g = 0-2 kg Molality of solution (m) =\[\frac{Mass\text{ }of\text{ }ethylene\text{ }glycol\text{ }/\text{ }Molar\text{ }mass}{Mass\text{ }of\text{ }solvent\text{ }in\text{ }kg}\] \[=\frac{(222.6g)/(62g\,mo{{l}^{-1}})}{0.2\,kg}=\[17\centerdot 95\]\,k{{g}^{-1}}\] = \[17\centerdot 95m\]
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