A) \[9\centerdot 8M\]
B) \[1\centerdot 9M\]
C) \[9\centerdot 1M\]
D) \[17\centerdot 95M\]
Correct Answer: C
Solution :
Calculation of the molarity of the solution Total mass of solution = Mass of solute + Mass solvent =\[222\centerdot 6+200=422\centerdot 6g\] Density of solution = \[1\centerdot 072g\,\,m{{L}^{-1}}\] Volume of solution =\[\frac{Mass\text{ }of\text{ }solution}{Density\text{ }of\text{ }solution}\] = \[\frac{\left( 422.6\text{ }g \right)}{\left( 1.072g\,m{{L}^{-1}} \right)}\] = 394.2 mL = 0-3942L. Molarity of solution (M) = \[\frac{Mass\text{ }of\text{ }ethylene\text{ }glycol\text{ }/\text{ }Molar\text{ }mass}{Volume\text{ }of\text{ }solution\text{ }in\text{ }litres}\] \[=\frac{(222.6\,g)/\left( 62g\,mo{{l}^{-1}} \right)}{\left( 0.3942\,L \right)}=9.10\,mol\,{{L}^{-1}}\]
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