A) \[0\centerdot 495g\]
B) \[49\centerdot 5g\]
C) \[4\centerdot 95g\]
D) 495 g.
Correct Answer: D
Solution :
\[\Delta {{T}_{f}}\]= 273-258=15K \[\Delta {{T}_{f}}={{K}_{f}}.\frac{{{W}_{2}}}{{{M}_{2}}}.\frac{1000}{{{W}_{1}}}\] or \[{{W}_{2}}=\frac{\Delta {{T}_{f}}.{{M}_{2}}.{{W}_{1}}}{{{K}_{f}}.1000}=\frac{15\times 62\times 1000}{1.86\times 1000}\] =500g
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