A) \[180{}^\circ \]
B) \[270{}^\circ \]
C) \[300{}^\circ \]
D) \[360{}^\circ \]
Correct Answer: C
Solution :
| \[\angle P'=\angle P=115{}^\circ \] |
| \[\angle Q'=\angle Q=95{}^\circ \] |
| \[\angle R'=\angle R=65{}^\circ \] and \[\angle S'=\angle S=85{}^\circ \] |
| \[\therefore \,\,\angle P'+\angle Q'+\angle R'+\angle S'=115{}^\circ +95{}^\circ +65{}^\circ +85{}^\circ =360{}^\circ \] (i.e., the sum of angles of quadrilateral \[P'Q'R'S'\] is \[360{}^\circ \]. |
| So, option [d] is correct. |
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