10th Class Mathematics Triangles Question Bank Case Based (MCQs) - Triangles

  • question_answer
    The sum of angles of quadrilateral P'Q'R'S' is:

    A) \[180{}^\circ \]

    B) \[270{}^\circ \]

    C) \[300{}^\circ \]

    D) \[360{}^\circ \]

    Correct Answer: C

    Solution :

    \[\angle P'=\angle P=115{}^\circ \]
    \[\angle Q'=\angle Q=95{}^\circ \]
    \[\angle R'=\angle R=65{}^\circ \] and \[\angle S'=\angle S=85{}^\circ \]
    \[\therefore \,\,\angle P'+\angle Q'+\angle R'+\angle S'=115{}^\circ +95{}^\circ +65{}^\circ +85{}^\circ =360{}^\circ \] (i.e., the sum of angles of quadrilateral \[P'Q'R'S'\] is \[360{}^\circ \].
    So, option [d] is correct.

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