10th Class Mathematics Triangles Question Bank Case Based (MCQs) - Triangles

  • question_answer
    The straight line distance between A and B is:

    A) \[\sqrt{5}+\sqrt{6.56}+\sqrt{6.56}+\sqrt{7.24}\]

    B) \[\sqrt{5.15}+\sqrt{6.21}+\sqrt{6.21}+\sqrt{7}\]

    C) \[\sqrt{5}+\sqrt{6}+\sqrt{6}+\sqrt{7}\]

    D) None of the above

    Correct Answer: A

    Solution :

    Using the concept of Pythagoras theorem,
    \[AB=\sqrt{{{(1)}^{2}}+{{(2)}^{2}}}+\sqrt{{{(2)}^{2}}+{{(1.6)}^{2}}}+\sqrt{{{(2)}^{2}}+{{(1.6)}^{2}}}\] \[+\sqrt{{{(2)}^{2}}+{{(1.8)}^{2}}}\]
    \[=\sqrt{1+4}+\sqrt{4+2.56}+\sqrt{4+2.56}+\sqrt{4+3.24}\]
    \[=\sqrt{5}+\sqrt{6.56}+\sqrt{6.56}+\sqrt{7.24}\]
    So, option [a] is correct.


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