10th Class Mathematics Triangles Question Bank Case Based (MCQs) - Triangles

  • question_answer
    The distance between their tops i.e., Length of AB is:

    A) \[\sqrt{1961}\,m\]

    B) \[\sqrt{802}\,m\]

    C) \[29\,m\]

    D) \[41\,m\]

    Correct Answer: C

    Solution :

    From the figure we note that
    and       \[AC=20m.\]
    Therefore, by Pythagoras theorem,
    \[A{{B}^{2}}=A{{C}^{2}}+B{{C}^{2}}={{20}^{2}}+{{21}^{2}}=400+441=841\]\[\Rightarrow \,\,\,\,\,\,\,\,\,AB=29\,m\]
    So, option [c] is correct.

You need to login to perform this action.
You will be redirected in 3 sec spinner