A) 16m
B) 32m
C) 20m
D) 8m
Correct Answer: A
Solution :
Given, HC = 40 cm Let length of the shadow of Ajay's house be HF = l m Since, \[\Delta HFG\tilde{\ }\Delta HCD\] \[\therefore \,\,\,\,\,\frac{HF}{HC}=\frac{FG}{CD}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\frac{l}{40}=\frac{40}{100}\] \[\Rightarrow \,\,\,\,l=\frac{40\times 40}{100}=16\,m\]You need to login to perform this action.
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