Directions: Q. 1 to 5 |
Vijay is trying to find the average height of a tower near his house. |
He is using the properties of similar triangles. The height of Vijay's house, if 20 m when Vijay's house casts a shadow 10m long on the ground. |
At the same time, the tower casts a shadow 50 m long on the ground and the house of Ajay casts 20 m shadow on the ground. |
Based on the above information, answer the following questions |
A) 20m
B) 50m
C) 100m
D) 200m
Correct Answer: C
Solution :
Let CD = h m be the height of the tower. Let BE = 20 m be the height of Vijay's house and GF be the height of Ajay's house, |
\[\Delta ACD\tilde{\ }ABE\] |
\[\therefore \frac{AC}{AB}=\frac{CD}{EB}\] |
\[\Rightarrow \frac{50}{10}=\frac{h}{20}\] |
\[\Rightarrow h=100m\] |
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