A) 0.55
B) 0.87
C) 0.37
D) 0.66
Correct Answer: C
Solution :
The mole fraction of the gas in solution \[x=\frac{p}{{{K}_{H}}}=\frac{1}{150\times {{10}^{3}}}\] If n is the number of moles of gas in a solution of 1 L of water containing 55.5 mol then \[x=\frac{n}{n+55.5}\]or, \[\frac{n}{55.5}\]=\[\frac{1}{150\times {{10}^{3}}}\] [n + 5.55 \[\approx \] 55.5, as n is very small] \[n=\frac{55.5}{150}\times {{10}^{-3}}=0.37\]millimolesYou need to login to perform this action.
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