| Directions: (Q. 16 to 20) |
| Case IV: Read the passage given below and answer the following questions from 16 to 20. |
| Nitric acid reacts with most of the metals (except noble metals like gold and platinum) and non- metals. Towards its reaction with metals, \[HN{{O}_{3}}\]acts as an acid as well as an oxidising agent. Like other acids, \[HN{{O}_{3}}\] liberate nascent hydrogen from metals which further reduces the nitric acid into number of products like NO, \[N{{O}_{2}}\], \[{{N}_{2}}O\] or \[N{{H}_{3}}\]. The different stages of reduction of nitric acid are : |
| \[\overset{+5}{\mathop{HN{{O}_{3}}}}\,\xrightarrow{+{{e}^{-}}}\overset{+4}{\mathop{N{{O}_{2}}}}\,\xrightarrow{+2{{e}^{-}}}\overset{+2}{\mathop{NO}}\,\xrightarrow[NaOH]{+{{e}^{-}}}{{\overset{+1}{\mathop{N}}\,}_{2}}O\xrightarrow{+4{{e}^{-}}}\overset{-3}{\mathop{N{{H}_{3}}}}\,\] The product of the reduction of \[HN{{O}_{3}}\] depends upon the nature of the metal, concentration of nitric acid and temperature. |
A) \[Pb+dil.\,HN{{O}_{3}}\to \]
B) \[Hg+dil.\,HN{{O}_{3}}\to \]
C) \[Zn+dil.\,HN{{O}_{3}}\to \]
D) \[Cu+dil.\,HN{{O}_{3}}\to \]
Correct Answer: C
Solution :
\[4Zn+10HN{{O}_{3}}\to 4Zn{{\left( N{{O}_{3}} \right)}_{2}}+5{{H}_{2}}O+\underset{Laughing\,gas}{\mathop{{{N}_{2}}O}}\,\]
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