A) oxidising agent
B) reducing agent
C) both oxidising as well as reducing agent
D) cannot be predicted.
Correct Answer: C
Solution :
In \[S{{O}_{2}}\], sulphur having +4 oxidation state, so it can lose its two more electrons to attain +6 oxidation state. It can gain electrons to attain its lowest oxidation state of -2. Therefore, it can behave as both reducing and oxidising agent.You need to login to perform this action.
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