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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Cathode Rays and Positive Rays

  • question_answer
    In the Millikan's experiment, the distance between two horizontal plates is 2.5 cm and the potential difference applied is 250 V. The electric field between the plates will be

    A)            900 V/m                                 

    B)            10000 V/m

    C)            625 V/m                                 

    D)            6250 V/m

    Correct Answer: B

    Solution :

               Electric field \[=\frac{V}{d}=\frac{250}{2.5\times {{10}^{-2}}}=10000\ V/m\].


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