A) \[\frac{{{\nu }_{1}}-{{\nu }_{2}}}{k-1}\]
B) \[1.9\times {{10}^{6}}m/s\]
C) \[1.9\times {{10}^{7}}m/s\]
D) \[2\sqrt{2}V\]
Correct Answer: C
Solution :
If the voltage given is V, then the energy of electron \[\frac{1}{2}m{{v}^{2}}=eV\Rightarrow v=\sqrt{\frac{2eV}{m}}\] \[=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 1000}{9.1\times {{10}^{-31}}}}=1.875\times {{10}^{7}}\]\[\approx 1.9\times {{10}^{7}}m/s\]
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