A) \[1.6\times {{10}^{-19}}coulomb\]
B) \[4.8\times {{10}^{-10}}stat\ coulomb\]
C) \[1.76\times {{10}^{11}}coulomb/kg\]
D) \[|8|\times {{10}^{-15}}Hz\]
Correct Answer: C
Solution :
\[\frac{e}{m}=\frac{1.6\times {{10}^{-19}}}{9.1\times {{10}^{-31}}}=1.76\times {{10}^{11}}C/kg\]
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