JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Cathode Rays and Positive Rays

  • question_answer
    An electron is accelerated through a potential difference of 200 volts. If \[e/m\] for the electron be \[1.6\times {{10}^{11}}\] coulomb/kg, the velocity acquired by the electron will be [MP PET 2000]

    A)            \[8\times {{10}^{6}}\,m/s\]   

    B)            \[8\times {{10}^{5}}\,m/s\]

    C)            \[5.9\times {{10}^{6}}\,m/s\]                                           

    D)            \[5.9\times {{10}^{5}}\,m/s\]

    Correct Answer: A

    Solution :

                       \[\frac{1}{2}m{{v}^{2}}=QV\Rightarrow v=\sqrt{\frac{2QV}{m}}=\sqrt{2\left( \frac{e}{m} \right)V}\]            \[\Rightarrow v=\sqrt{2\times 1.6\times {{10}^{11}}\times 200}=8\times {{10}^{6}}m/s\].


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