A) \[2.76\times {{10}^{12}}C/kg\]
B) \[1.76\times {{10}^{11}}C/kg\]
C) \[0.76\times {{10}^{12}}C/kg\]
D) None of these
Correct Answer: B
Solution :
\[\frac{1}{2}m{{v}^{2}}=eV\,\,\Rightarrow \,\,\frac{e}{m}=\frac{{{v}^{2}}}{2V}=\frac{{{(8.4\times {{10}^{6}})}^{2}}}{2\times 200}\]\[=1.76\times {{10}^{11}}\,\frac{C}{kg}.\]You need to login to perform this action.
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