JEE Main & Advanced
Physics
Photo Electric Effect, X- Rays & Matter Waves
Question Bank
Cathode Rays and Positive Rays
question_answer
In the Millikan's experiment, the distance between two horizontal plates is 2.5 cm and the potential difference applied is 250 V. The electric field between the plates will be
A) 900 V/m
B) 10000 V/m
C) 625 V/m
D) 6250 V/m
Correct Answer:
B
Solution :
Electric field \[=\frac{V}{d}=\frac{250}{2.5\times {{10}^{-2}}}=10000\ V/m\].