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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Cathode Rays and Positive Rays

  • question_answer
    An electron is accelerated through a p.d. of 45.5 volt. The velocity acquired by it is (in ms-1)                          [AIIMS 2004]

    A)            \[4\times {{10}^{6}}\]      

    B)            \[4\times {{10}^{4}}\]

    C)            \[{{10}^{6}}\]                       

    D)            Zero

    Correct Answer: A

    Solution :

               \[v=\sqrt{\frac{2eV}{m}}=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 45.5}{9.1\times {{10}^{-31}}}}\]\[=\,4\times {{10}^{6}}\,m/s\]


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