A) \[1.0\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
B) \[1.76\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
C) \[1.80\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
D) \[1.85\times {{10}^{11}}C\text{-}k{{g}^{-1}}\]
Correct Answer: C
Solution :
\[\frac{e}{m}=\frac{{{E}^{2}}}{2V{{B}^{2}}}=\frac{{{(3.6\times {{10}^{4}})}^{2}}}{2\times 2.5\times {{10}^{3}}\times {{(1.2\times {{10}^{-3}})}^{2}}}\] \[=1.8\times {{10}^{11}}C/kg\].You need to login to perform this action.
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