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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Cathode Rays and Positive Rays

  • question_answer
    In Millikan?s oil drop experiment, an oil drop of mass \[16\times {{10}^{-6}}kg\] is balanced by an electric field of \[{{10}^{6}}V/m.\] The charge in coulomb on the drop, assuming \[g=10\,m/{{s}^{2}}\] is                                             [UP SEAT 2005]

    A)            \[6.2\times {{10}^{-11}}\]      

    B)            \[16\times {{10}^{-9}}\]          

    C)            \[16\times {{10}^{-11}}\]        

    D)            \[16\times {{10}^{-13}}\]

    Correct Answer: C

    Solution :

               \[eE=mg\]Þ \[e=\frac{mg}{E}\] \[=\frac{16\times {{10}^{-6}}\times 10}{{{10}^{6}}}=16\times {{10}^{-11}}\]C.


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