A) 3, 6
B) 6, 3
C) 4, 6
D) 6, 4
E) 6, 8
Correct Answer: D
Solution :
\[_{90}T{{h}^{232}}\,\xrightarrow{{}}{{\,}_{82}}P{{b}^{208}}\] No. of \[\alpha \]- particle \[\Rightarrow \frac{232-208}{4}=6\] No. of \[\beta \]- particle \[\Rightarrow \,82-[90-6\times 2]=4\]You need to login to perform this action.
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