A) 1 and 1
B) 1 and 2
C) 2 and 1
D) 2 and 2
Correct Answer: A
Solution :
\[_{92}{{U}^{238}}\xrightarrow{{}}{{\,}_{90}}T{{h}^{234}}\xrightarrow{{}}{{\,}_{91}}P{{a}^{234}}\] No. of \[\alpha \] particle \[=\frac{238-234}{4}=\frac{4}{4}=1\] No. of \[\beta \] particle \[=91-90=1\]You need to login to perform this action.
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