A) \[N{{H}_{4}}\]
B) \[{{N}_{2}}\]
C) \[{{H}_{2}}\]
D) \[C{{l}_{2}}\]
Correct Answer: C
Solution :
\[2N{{H}_{4}}Cl+Zn\to 2N{{H}_{3}}+ZnC{{l}_{2}}+{{H}_{2}}\uparrow \].
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