A) \[{{H}_{2}}\] is evolved at cathode
B) \[N{{H}_{3}}\] is produced at anode
C) \[C{{l}_{2}}\] is obtained at cathode
D) \[{{O}_{2}}\] is produced
Correct Answer: A
Solution :
When platinum electrodes are dipped in dilute solution \[{{H}_{2}}S{{O}_{4}}\] than \[{{H}_{2}}\] is evolved at cathode.
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