A) \[201.28\,oh{{m}^{-1}}\,c{{m}^{2}}\,mo{{l}^{-1}}\]
B) \[390.71\,oh{{m}^{-1}}c{{m}^{2}}\,mo{{l}^{-1}}\]
C) \[698.28\,oh{{m}^{-1}}\,c{{m}^{2}}\,mo{{l}^{-1}}\]
D) \[540.48\,oh{{m}^{-1}}c{{m}^{2}}\,mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[\wedge _{m}^{o}(C{{H}_{3}}COOH)=\,\,\] \[{{\wedge }^{o}}(C{{H}_{3}}COONa)\]\[+{{\wedge }^{o}}(HCl)-\,\,{{\wedge }^{o}}(NaCl)\] \[=91+426.16-126.45=390.71\,\,oh{{m}^{-1}}c{{m}^{2}}mo{{l}^{-1}}\].You need to login to perform this action.
You will be redirected in
3 sec