A) \[Pt|{{H}_{2}}(g),1\text{bar }\!\!|\!\!\text{ 1}M\ KCl(aq)|AgCl(s)|Ag(s)\]
B) \[Pt(s)|{{H}_{2}}(g),\ 1\text{bar }\!\!|\!\!\text{ }\ 1M\ HCl(aq)||1M\ A{{g}^{+}}(aq)|Ag(s)\]
C) \[Pt(s)|{{H}_{2}}(g),\ 1\text{bar }\!\!|\!\!\text{ }\ 1M\ HCl(aq)|AgCl(s)|Ag(s)\]
D) \[Pt(s)|{{H}_{2}}(g),\ 1\text{bar }\!\!|\!\!\text{ }\ 1M\ HCl(aq)|Ag(s)|AgCl(s)\]
Correct Answer: B
Solution :
2AgCl(s) + H2(g) ® 2HCl(aq.) + 2Ag(s) The activities of solids and liquids are takes as unity and at low concentrations, the activity of a solute is approximated to its molarity. Th cell reaction will be Pt(s) | H2(g), 1 bar | H+(aq) 1 M | AgCl(aq) 1 M | Ag(s)You need to login to perform this action.
You will be redirected in
3 sec