A) \[P{{b}^{2+}}+2{{e}^{-}}\to Pb\]
B) \[P{{b}^{2+}}+SO_{4}^{2-}\to PbS{{O}_{4}}\]
C) \[Pb\to P{{b}^{2+}}+2{{e}^{-}}\]
D) \[PbS{{O}_{4}}+2{{H}_{2}}O\to 2Pb{{O}_{2}}+4SO_{4}^{2-}+2{{e}^{-}}\]
Correct Answer: D
Solution :
\[PbS{{O}_{4}}+2{{H}_{2}}O\to 2Pb{{O}_{2}}+4SO_{4}^{-\,-}+2{{e}^{-}}\].
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