A) \[288.5\ oh{{m}^{-1}}c{{m}^{2}}gme{{q}^{-1}}\]
B) \[289.5\ oh{{m}^{-1}}c{{m}^{2}}gme{{q}^{-1}}\]
C) \[388.5\ oh{{m}^{-1}}c{{m}^{2}}gme{{q}^{-1}}\]
D) \[59.5\ oh{{m}^{-1}}c{{m}^{2}}gme{{q}^{-1}}\]
Correct Answer: C
Solution :
\[Cl\underset{{{\lambda }_{ClC{{H}_{2}}COONa}}+}{\mathop{C{{H}_{2}}COONa}}\,+\underset{{{\lambda }_{HCl}}}{\mathop{HCl}}\,\underset{=}{\mathop{\to }}\,\underset{{{\lambda }_{ClC{{H}_{2}}COOH}}+}{\mathop{ClC{{H}_{2}}COOH}}\,+\underset{{{\lambda }_{NaCl}}}{\mathop{NaCl}}\,\] \[224+203={{\lambda }_{ClC{{H}_{2}}COOH}}+38.2\] \[{{\lambda }_{ClC{{H}_{2}}COOH}}=427-38.2=388.8\ oh{{m}^{-1}}c{{m}^{2}}gme{{q}^{-1}}\].You need to login to perform this action.
You will be redirected in
3 sec