A) Lead dioxide dissolves
B) Sulphuric acid is regenerated
C) The lead electrode becomes coated with lead sulphate
D) The amount of sulphuric acid decreases
Correct Answer: B
Solution :
During charging of a lead storage battery, the reaction at the anode and cathode are Anode: \[PbS{{O}_{4}}+2{{e}^{-}}\to Pb+SO_{4}^{2-}\] Cathode: \[PbS{{O}_{4}}+2{{H}_{2}}O\to Pb{{O}_{2}}+4{{H}^{+}}+SO_{4}^{2-}+2{{e}^{-}}\] In both the reactions \[{{H}_{2}}S{{O}_{4}}\] is regenerated.
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