A) \[1L={{10}^{3}}\,ml\]
B) \[1\,d{{m}^{3}}=1\,L\]
C) \[1\,L={{10}^{3}}{{m}^{3}}\]
D) \[1L={{10}^{3}}\,c{{m}^{3}}\]
Correct Answer: C
Solution :
1\[L={{10}^{-3}}{{m}^{3}}={{10}^{3}}c{{m}^{3}}=1d{{m}^{3}}={{10}^{3}}ml\].
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