A) \[4N\] (Attractive)
B) \[4N\] (Repulsive)
C) \[8N\] (Repulsive)
D) Zero
Correct Answer: D
Solution :
Resultant charges after adding the ? 2C be \[(-\,2+2)=0\] and \[(-\,2+6)=+\,4C\] Þ F\[=\frac{k\,{{Q}_{1}}{{Q}_{2}}}{{{r}^{2}}}=k\times \frac{0\times 4}{{{r}^{2}}}=0\]
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