A) \[16\,\mu \,C\]
B) \[-16\,\mu \,C\]
C) \[32\,\mu \,C\]
D) \[-32\,\mu \,C\]
Correct Answer: A
Solution :
\[Q=ne={{10}^{14}}\times 1.6\times {{10}^{-19}}\]Þ \[Q=1.6\times {{10}^{-5}}C=16\mu C\] Electrons are removed, so chare will be positive.
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