A) \[9\times {{10}^{9}}N{{C}^{2}}/{{m}^{2}}\]
B) \[8.85\times {{10}^{-12}}N{{m}^{2}}/{{C}^{2}}sec\]
C) \[8.85\times {{10}^{-12}}{{C}^{2}}/N{{m}^{2}}\]
D) \[9\times {{10}^{9}}{{C}^{2}}/N{{m}^{2}}\]
Correct Answer: C
Solution :
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