2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electrostatics & Capacitance

JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    A charge \[Q\] is divided into two parts of \[q\] and \[Q-q\]. If the coulomb repulsion between them when they are separated is to be maximum, the ratio of \[\frac{Q}{q}\] should be          [MP PET 1997]

    A)                    2

    B)                    \[1/2\]

    C)                    4           

    D)                    \[1/4\]

    Correct Answer: A

    Solution :

                         Let separation between two parts be r Þ \[F=k.q\frac{(Q-q)}{{{r}^{2}}}\]                    For F to be maximum \[\frac{dF}{dq}=0\] Þ \[\frac{Q}{q}=\frac{2}{1}\]           


You need to login to perform this action.
You will be redirected in 3 sec spinner