A) 0.9 N
B) 1.8 N
C) 2.7 N
D) 3.6 N
Correct Answer: B
Solution :
FA = force on C due to charge placed at A \[=9\times {{10}^{9}}\times \frac{{{10}^{-6}}\times 2\times {{10}^{-6}}}{{{(10\times {{10}^{-2}})}^{2}}}=1.8\,N\] FB = force on C due to charge placed at B \[=9\times {{10}^{9}}\times \frac{{{10}^{-6}}\times 2\times {{10}^{-6}}}{{{(0.1)}^{2}}}=1.8N\]You need to login to perform this action.
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