A) 1.89 N
B) 2.44 N
C) 0.144 N
D) 3.144 N
Correct Answer: C
Solution :
By using \[F=9\times {{10}^{9}}.\frac{{{Q}^{2}}}{{{r}^{2}}}\] Þ \[F=9\times {{10}^{9}}.\frac{{{(2\times {{10}^{-6}})}^{2}}}{{{(0.5)}^{2}}}=0.144N\]You need to login to perform this action.
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