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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    Two charges each equal to \[2\mu C\] are 0.5m apart. If both of them exist inside vacuum, then the force between them is [CPMT 2001]

    A)            1.89 N                                     

    B)            2.44 N

    C)            0.144 N                                   

    D)            3.144 N

    Correct Answer: C

    Solution :

                         By using \[F=9\times {{10}^{9}}.\frac{{{Q}^{2}}}{{{r}^{2}}}\]  Þ  \[F=9\times {{10}^{9}}.\frac{{{(2\times {{10}^{-6}})}^{2}}}{{{(0.5)}^{2}}}=0.144N\]


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