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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    Two particle of equal mass \[m\] and charge \[q\] are placed at a distance of 16 cm. They do not experience any force. The value of \[\frac{q}{m}\] is                              [MP PET 2003]

    A)            l      

    B)            \[\sqrt{\frac{\pi {{\varepsilon }_{0}}}{G}}\]

    C)            \[\sqrt{\frac{G}{4\pi {{\varepsilon }_{0}}}}\]             

    D)            \[\sqrt{4\pi {{\varepsilon }_{0}}G}\]

    Correct Answer: D

    Solution :

                         They will not experience any force if \[|\overrightarrow{{{F}_{G}}}|\,=\,|\overrightarrow{{{F}_{e}}}|\] Þ\[G\frac{{{m}^{2}}}{{{(16\times {{10}^{-2}})}^{2}}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}^{2}}}{{{(16\times {{10}^{-2}})}^{2}}}\]Þ \[\frac{q}{m}=\sqrt{4\pi {{\varepsilon }_{0}}G}\]


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