A) \[8\times {{10}^{-5}}\]
B) \[80\times {{10}^{-17}}\]
C) \[5\times {{10}^{14}}\]
D) \[1.28\times {{10}^{-17}}\]
Correct Answer: C
Solution :
By \[Q=Ne\] or \[N=\frac{Q}{e}\therefore N=\frac{80\times {{10}^{-6}}}{1.6\times {{10}^{-19}}}=5\times {{10}^{14}}\]
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