JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    Two point charges placed at a certain distance r in air exert a force F on each other. Then the distance r' at which these charges will exert the same force in a medium of dielectric constant k is given by              [EAMCET 1990; MP PMT 2001]

    A)            r     

    B)            r/k

    C)            \[r/\sqrt{k}\]                       

    D)            \[r\sqrt{k}\]

    Correct Answer: C

    Solution :

                 \[F=F'\] or \[\frac{{{Q}_{1}}{{Q}_{2}}}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}=\frac{{{Q}_{1}}{{Q}_{2}}}{4\pi {{\varepsilon }_{0}}r{{'}^{2}}K}\Rightarrow r'=\frac{r}{\sqrt{K}}\]


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