JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    The ratio of the forces between two small spheres with constant charge \[(a)\] in air \[(b)\] in a medium of dielectric constant K is                                                                     [MNR 1998]

    A)                    1 : K                                  

    B)                    K : 1

    C)                    \[1:{{K}^{2}}\]              

    D)                    \[{{K}^{2}}:1\]

    Correct Answer: B

    Solution :

               \[{{F}_{a}}=\frac{{{q}_{1}}{{q}_{2}}}{4\pi {{\varepsilon }_{0}}{{r}^{2}}},\,{{F}_{b}}=\frac{{{q}_{1}}{{q}_{2}}}{K4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] Þ \[{{F}_{a}}:{{F}_{b}}=K:1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner