A) Decreases \[k\] times
B) Remains unchanged
C) Increases \[k\] times
D) Increases \[{{k}^{-1}}\] times
Correct Answer: A
Solution :
\[{F}'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}=\frac{F}{K}\] If F is the force in air, then \[{F}'\] is less than F since \[K>1\].You need to login to perform this action.
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