A) F
B) 3F/4
C) F/2
D) F/4
Correct Answer: A
Solution :
Initially \[F=k\frac{{{Q}^{2}}}{{{r}^{2}}}\] ....... (i) Finally Force on C due to A, \[{{F}_{A}}=\frac{k{{(Q/2)}^{2}}}{{{(r/2)}^{2}}}=\frac{k{{Q}^{2}}}{{{r}^{2}}}\] Force on C due to B, \[{{F}_{B}}=\frac{KQ(Q/2)}{{{(r/2)}^{2}}}=\frac{2K{{Q}^{2}}}{{{r}^{2}}}\] \ Net force on C, \[{{F}_{net}}={{F}_{B}}-{{F}_{A}}=\frac{k{{Q}^{2}}}{{{r}^{2}}}=F\]You need to login to perform this action.
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