A) \[2.4\times \text{1}{{0}^{3}}N\] (attractive)
B) \[2.4\times \text{1}{{0}^{9}}N\] (attractive)
C) \[\text{1}.\text{5}\times \text{1}{{0}^{\text{3}}}N\] (repulsive)
D) \[\text{1}.\text{5}\times \text{1}{{0}^{\text{3}}}N\] (attractive)
Correct Answer: D
Solution :
\[F\propto {{Q}_{1}}{{Q}_{2}}\] Þ \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{Q}_{1}}{{Q}_{2}}}{{{Q}_{1}}'{{Q}_{2}}'}\] \[=\frac{3\times {{10}^{-6}}\times 8\times {{10}^{-6}}}{(3\times {{10}^{-6}}-6\times {{10}^{-6}})(8\times {{10}^{-6}}-6\times {{10}^{-6}})}=\frac{3\times 8}{-\,3\times 2}=-\frac{4}{1}\] Þ \[{{F}_{2}}=-\frac{{{F}_{1}}}{4}=-\frac{6\times {{10}^{-3}}}{4}=-1.5\times {{10}^{-3}}N\] (Attractive)You need to login to perform this action.
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