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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is                                               [DCE 2004]

    A)                    F / 8                                             

    B)                    F / 4           

    C)                    4 F                                     

    D)                    F / 16

    Correct Answer: D

    Solution :

                 \[F=k.\frac{{{Q}^{2}}}{{{r}^{2}}}\]. If Q is halved, r is doubled then \[F\to \frac{1}{16}\text{times}\]


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