A) 12.5 and 36.6
B) 25 and 75
C) 25 and 36.6
D) 25 and 80
Correct Answer: B
Solution :
% of C = \[\frac{12}{44}\times \frac{\text{Mass of }C{{O}_{2}}}{\text{Mass of substance}}\times 100\] = \[\frac{12\times 0.22}{44\times 0.24}\times 100\]= 25; C = 25, H = 1.66 Total = 26.6 = 100 - 26.6 = 73.4.You need to login to perform this action.
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